Optimal. Leaf size=111 \[ \frac{5 a^3 (B+C) \tan (c+d x)}{2 d}+\frac{a^3 (7 B+5 C) \tanh ^{-1}(\sin (c+d x))}{2 d}+\frac{(3 B+5 C) \tan (c+d x) \left (a^3 \sec (c+d x)+a^3\right )}{6 d}+a^3 B x+\frac{a C \tan (c+d x) (a \sec (c+d x)+a)^2}{3 d} \]
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Rubi [A] time = 0.204806, antiderivative size = 111, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 6, integrand size = 38, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.158, Rules used = {4072, 3917, 3914, 3767, 8, 3770} \[ \frac{5 a^3 (B+C) \tan (c+d x)}{2 d}+\frac{a^3 (7 B+5 C) \tanh ^{-1}(\sin (c+d x))}{2 d}+\frac{(3 B+5 C) \tan (c+d x) \left (a^3 \sec (c+d x)+a^3\right )}{6 d}+a^3 B x+\frac{a C \tan (c+d x) (a \sec (c+d x)+a)^2}{3 d} \]
Antiderivative was successfully verified.
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Rule 4072
Rule 3917
Rule 3914
Rule 3767
Rule 8
Rule 3770
Rubi steps
\begin{align*} \int \cos (c+d x) (a+a \sec (c+d x))^3 \left (B \sec (c+d x)+C \sec ^2(c+d x)\right ) \, dx &=\int (a+a \sec (c+d x))^3 (B+C \sec (c+d x)) \, dx\\ &=\frac{a C (a+a \sec (c+d x))^2 \tan (c+d x)}{3 d}+\frac{1}{3} \int (a+a \sec (c+d x))^2 (3 a B+a (3 B+5 C) \sec (c+d x)) \, dx\\ &=\frac{a C (a+a \sec (c+d x))^2 \tan (c+d x)}{3 d}+\frac{(3 B+5 C) \left (a^3+a^3 \sec (c+d x)\right ) \tan (c+d x)}{6 d}+\frac{1}{6} \int (a+a \sec (c+d x)) \left (6 a^2 B+15 a^2 (B+C) \sec (c+d x)\right ) \, dx\\ &=a^3 B x+\frac{a C (a+a \sec (c+d x))^2 \tan (c+d x)}{3 d}+\frac{(3 B+5 C) \left (a^3+a^3 \sec (c+d x)\right ) \tan (c+d x)}{6 d}+\frac{1}{2} \left (5 a^3 (B+C)\right ) \int \sec ^2(c+d x) \, dx+\frac{1}{2} \left (a^3 (7 B+5 C)\right ) \int \sec (c+d x) \, dx\\ &=a^3 B x+\frac{a^3 (7 B+5 C) \tanh ^{-1}(\sin (c+d x))}{2 d}+\frac{a C (a+a \sec (c+d x))^2 \tan (c+d x)}{3 d}+\frac{(3 B+5 C) \left (a^3+a^3 \sec (c+d x)\right ) \tan (c+d x)}{6 d}-\frac{\left (5 a^3 (B+C)\right ) \operatorname{Subst}(\int 1 \, dx,x,-\tan (c+d x))}{2 d}\\ &=a^3 B x+\frac{a^3 (7 B+5 C) \tanh ^{-1}(\sin (c+d x))}{2 d}+\frac{5 a^3 (B+C) \tan (c+d x)}{2 d}+\frac{a C (a+a \sec (c+d x))^2 \tan (c+d x)}{3 d}+\frac{(3 B+5 C) \left (a^3+a^3 \sec (c+d x)\right ) \tan (c+d x)}{6 d}\\ \end{align*}
Mathematica [B] time = 6.40118, size = 772, normalized size = 6.95 \[ a^3 \left (\frac{(\cos (c+d x)+1)^3 \sec ^6\left (\frac{c}{2}+\frac{d x}{2}\right ) \left (9 B \sin \left (\frac{d x}{2}\right )+11 C \sin \left (\frac{d x}{2}\right )\right )}{24 d \left (\cos \left (\frac{c}{2}\right )-\sin \left (\frac{c}{2}\right )\right ) \left (\cos \left (\frac{c}{2}+\frac{d x}{2}\right )-\sin \left (\frac{c}{2}+\frac{d x}{2}\right )\right )}+\frac{(\cos (c+d x)+1)^3 \sec ^6\left (\frac{c}{2}+\frac{d x}{2}\right ) \left (9 B \sin \left (\frac{d x}{2}\right )+11 C \sin \left (\frac{d x}{2}\right )\right )}{24 d \left (\sin \left (\frac{c}{2}\right )+\cos \left (\frac{c}{2}\right )\right ) \left (\sin \left (\frac{c}{2}+\frac{d x}{2}\right )+\cos \left (\frac{c}{2}+\frac{d x}{2}\right )\right )}+\frac{(\cos (c+d x)+1)^3 \sec ^6\left (\frac{c}{2}+\frac{d x}{2}\right ) \left (-3 B \sin \left (\frac{c}{2}\right )+3 B \cos \left (\frac{c}{2}\right )-8 C \sin \left (\frac{c}{2}\right )+10 C \cos \left (\frac{c}{2}\right )\right )}{96 d \left (\cos \left (\frac{c}{2}\right )-\sin \left (\frac{c}{2}\right )\right ) \left (\cos \left (\frac{c}{2}+\frac{d x}{2}\right )-\sin \left (\frac{c}{2}+\frac{d x}{2}\right )\right )^2}+\frac{(\cos (c+d x)+1)^3 \sec ^6\left (\frac{c}{2}+\frac{d x}{2}\right ) \left (-3 B \sin \left (\frac{c}{2}\right )-3 B \cos \left (\frac{c}{2}\right )-8 C \sin \left (\frac{c}{2}\right )-10 C \cos \left (\frac{c}{2}\right )\right )}{96 d \left (\sin \left (\frac{c}{2}\right )+\cos \left (\frac{c}{2}\right )\right ) \left (\sin \left (\frac{c}{2}+\frac{d x}{2}\right )+\cos \left (\frac{c}{2}+\frac{d x}{2}\right )\right )^2}+\frac{(-7 B-5 C) (\cos (c+d x)+1)^3 \sec ^6\left (\frac{c}{2}+\frac{d x}{2}\right ) \log \left (\cos \left (\frac{c}{2}+\frac{d x}{2}\right )-\sin \left (\frac{c}{2}+\frac{d x}{2}\right )\right )}{16 d}+\frac{(7 B+5 C) (\cos (c+d x)+1)^3 \sec ^6\left (\frac{c}{2}+\frac{d x}{2}\right ) \log \left (\sin \left (\frac{c}{2}+\frac{d x}{2}\right )+\cos \left (\frac{c}{2}+\frac{d x}{2}\right )\right )}{16 d}+\frac{1}{8} B x (\cos (c+d x)+1)^3 \sec ^6\left (\frac{c}{2}+\frac{d x}{2}\right )+\frac{C \sin \left (\frac{d x}{2}\right ) (\cos (c+d x)+1)^3 \sec ^6\left (\frac{c}{2}+\frac{d x}{2}\right )}{48 d \left (\cos \left (\frac{c}{2}\right )-\sin \left (\frac{c}{2}\right )\right ) \left (\cos \left (\frac{c}{2}+\frac{d x}{2}\right )-\sin \left (\frac{c}{2}+\frac{d x}{2}\right )\right )^3}+\frac{C \sin \left (\frac{d x}{2}\right ) (\cos (c+d x)+1)^3 \sec ^6\left (\frac{c}{2}+\frac{d x}{2}\right )}{48 d \left (\sin \left (\frac{c}{2}\right )+\cos \left (\frac{c}{2}\right )\right ) \left (\sin \left (\frac{c}{2}+\frac{d x}{2}\right )+\cos \left (\frac{c}{2}+\frac{d x}{2}\right )\right )^3}\right ) \]
Antiderivative was successfully verified.
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Maple [A] time = 0.084, size = 158, normalized size = 1.4 \begin{align*}{a}^{3}Bx+{\frac{B{a}^{3}c}{d}}+{\frac{5\,{a}^{3}C\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{2\,d}}+{\frac{7\,B{a}^{3}\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{2\,d}}+{\frac{11\,{a}^{3}C\tan \left ( dx+c \right ) }{3\,d}}+3\,{\frac{B{a}^{3}\tan \left ( dx+c \right ) }{d}}+{\frac{3\,{a}^{3}C\sec \left ( dx+c \right ) \tan \left ( dx+c \right ) }{2\,d}}+{\frac{B{a}^{3}\sec \left ( dx+c \right ) \tan \left ( dx+c \right ) }{2\,d}}+{\frac{{a}^{3}C\tan \left ( dx+c \right ) \left ( \sec \left ( dx+c \right ) \right ) ^{2}}{3\,d}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 0.95599, size = 286, normalized size = 2.58 \begin{align*} \frac{12 \,{\left (d x + c\right )} B a^{3} + 4 \,{\left (\tan \left (d x + c\right )^{3} + 3 \, \tan \left (d x + c\right )\right )} C a^{3} - 3 \, B a^{3}{\left (\frac{2 \, \sin \left (d x + c\right )}{\sin \left (d x + c\right )^{2} - 1} - \log \left (\sin \left (d x + c\right ) + 1\right ) + \log \left (\sin \left (d x + c\right ) - 1\right )\right )} - 9 \, C a^{3}{\left (\frac{2 \, \sin \left (d x + c\right )}{\sin \left (d x + c\right )^{2} - 1} - \log \left (\sin \left (d x + c\right ) + 1\right ) + \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + 18 \, B a^{3}{\left (\log \left (\sin \left (d x + c\right ) + 1\right ) - \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + 6 \, C a^{3}{\left (\log \left (\sin \left (d x + c\right ) + 1\right ) - \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + 36 \, B a^{3} \tan \left (d x + c\right ) + 36 \, C a^{3} \tan \left (d x + c\right )}{12 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 0.525894, size = 356, normalized size = 3.21 \begin{align*} \frac{12 \, B a^{3} d x \cos \left (d x + c\right )^{3} + 3 \,{\left (7 \, B + 5 \, C\right )} a^{3} \cos \left (d x + c\right )^{3} \log \left (\sin \left (d x + c\right ) + 1\right ) - 3 \,{\left (7 \, B + 5 \, C\right )} a^{3} \cos \left (d x + c\right )^{3} \log \left (-\sin \left (d x + c\right ) + 1\right ) + 2 \,{\left (2 \,{\left (9 \, B + 11 \, C\right )} a^{3} \cos \left (d x + c\right )^{2} + 3 \,{\left (B + 3 \, C\right )} a^{3} \cos \left (d x + c\right ) + 2 \, C a^{3}\right )} \sin \left (d x + c\right )}{12 \, d \cos \left (d x + c\right )^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.20201, size = 255, normalized size = 2.3 \begin{align*} \frac{6 \,{\left (d x + c\right )} B a^{3} + 3 \,{\left (7 \, B a^{3} + 5 \, C a^{3}\right )} \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 1 \right |}\right ) - 3 \,{\left (7 \, B a^{3} + 5 \, C a^{3}\right )} \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 1 \right |}\right ) - \frac{2 \,{\left (15 \, B a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} + 15 \, C a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} - 36 \, B a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - 40 \, C a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} + 21 \, B a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 33 \, C a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )\right )}}{{\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 1\right )}^{3}}}{6 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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